I need some help understanding clearing fractions. Example: -x+2/5=5-4/3x
-x+2/5=5-4/3x
Is the equation a) \(-x + \frac{2}{5} = 5 - \frac{4}{3x}\) b) \(\frac{-x + 2}{5} = 5- \frac{4}{3x}\) c) None of the above.
a)
the x is not below the 4
oh, good. That's even better.
\[-x + \frac{2}{5} = 5 - \frac{4}{3}x\]
Right?
Yes
Ok, so lets start by getting all of our 'like' terms to have the same denominator. To do that, we'll make the -x into a fraction with a 3 on bottom. How can we do that?
-x/3
Nearly, but it must maintain equivalence. 3/3 is 1 right?
-1x/3
No. Stop guessing and listen. 3/3 = 1. Right?
yes
Ok, and 1 times any number gives you the same number right? a*1 = a
right
so then: \[a = 1*a = \frac{3}{3}*a = \frac{3a}{3} = a\]
Did you follow that? Sometimes it's hard to read on one line.
yes
Ok, so what is -x as a multiple of 1/3?
The basic rule of thumb for equivalent fractions is: You can multiply the top and bottom by the same thing and the value doesn't change.
don't know
So we have: \[\frac{-x}{1}\] And we want to get a 3 on the bottom, so we multiply the bottom times 3. That means we have to multiply the top by 3 also to keep it having the same value as -x.
\[\frac{-3x}{3} = -x\] Right?
-3x/3
Right.
So lets do the same thing to the 5 on the right side of the equation. We need to get a 5 on bottom, so what would it be.. We have: \[\frac{5}{1}\]
5/1+2/5
Ok, we have this (after changing the denominator on -x) \[\frac{-3x}{3} + \frac{2}{5} = 5 -\frac{4x}{3}\]
Can you use algebra to get all the terms with x on one side, and all the terms without x on the other?
I appreciate you trying to help me, but I need to see the example I gave solved from the beginning to the end. It isn't working very well showing me a step here and there.
Hello
One second.
Starting from \[\frac{-3x}{3} + \frac{2}{5} = 5 - \frac{4x}{3}\] Can you solve for x?
James are you there?
-x+2/5=5-4x/3
Because you have denominators and an = sign, you need to find a common denominator. What is the common denominator using 5 and 3
15
So multiply the whole equation by 15.
Yes.. every term.
15(-x+2/5)=15(5-4/3x)
Yep. And distribute.
(15)(-x) + (15)(2) (15)(5) - (15)(4x) ----- = ------- 5 3
Cancel out the denominators into the numerators.
(15)(-x) + (3)(2) = (15)(5) - 5(4x)
-15x + 6 = 75 - 20x
Now solve for x in the usual way.
Blexting, let him do it.
I don't know
James when you are solving and you see x's on both sides of the equation, I like to get rid of the smallest one. Which one is smaller -15x or -20x
-20x
so add 20x to both sides
James, if you have an equation: 5x + 4 = 4 How do you solve for x?
What do you get James when you +20x to both sides?
20x-15x+6=75-20x=20X
THE LAST ONE should be a plus sign
Good so add like terms.
-5x+6=75-x
20x - 15x (20 - 15 = ?)
-20x + 20x = (-20 + 20 = ?)
5
So you have 5x + 6 = 75 (because your -20 + 20 = 0 so you don't have any x's on that side)
Then what?
how do you get the x by itself.. do you get rid of the 5 first or the 6 first?
5x=75-6
Yes... but what is 75-6 5x = 69
but isn't the answer suppose to be x=69/5 and how do you get that?
Yes... divide in you calculator. 13.8
where are you getting 13.8
Once again, I appreciate the help, but I need to see the problem solved from beginning to end. It isn't helping trying to get me to figure out something I don't know. I have to see it work.
would it be 5x-69 x=69÷5 x=69/5
5x=69 x=69÷5 x=69/5
Hello, is anybody there?
I don't appreciate being ignored. Just because I don't understand doesn't mean I should not be helped. If I knew this crap I wouldn't be here in the first place. Thanks for nothing, and I will not recommend this place to anyone.
James, nobody knows that you entered another comment on this page unless they are sitting here watching your post... You need to go and "ask a question" and someone will see it and respond...
Join our real-time social learning platform and learn together with your friends!