Question

Which of the coordinate pairs below is a solution to the following system of equations?

x2 + y2 = 157 x + y = 17

Answer 1

I believe the general way of solving these kinds of equations is to substitute the values of the coordinate pair for x and y in the equation, and see if the two sides match up.

For example, if one of the given coordinate pairs is (2,5)

Then, we will substitute x = 2, and y = 5.

So, the equation will become:

2^2 + 5^2 = 157*2 + 5 = 17

29 = 319 = 17

This is obviously not true, so (2,5) is not the solution

Answer 2

is it (3, 10)

Answer 3

Try substituting x = 3 and y = 10 in your equation to find out!

Answer 4

First of all you have two = signs in here... is that correct?

Answer 5

yea

Answer 6

Oh is it two equations.
x^2 + y^2 = 157
AND
x + y = 17

Answer 7

yea

Answer 8

Then the answer (x,y) will be where the x + y = 17 and the
x^2 + y^2 = 17

Answer 9

sorry x^2 + y^2 = 157

Answer 10

is it (3,10)

Answer 11

does 3 + 10 = 17

Answer 12

no 30 Idk , i took a wild Guess of tha answer

Answer 13

Oh.. I thought you had multiple choice.

Answer 14

If you have to work it out... it is a bit of a long process... here we go.

Answer 15

x + y = 17

y = 17 - x

we substitute that into the other equation.

x^2 + y^2 = 157
x^2 + (17-x)^2 = 157
x^2 + (17-x)(17-x) = 157 you foil the 17-x
x^2 + 289 - 17x - 17x + x^2 = 157
2x^2 - 34x + 289 = 157 (add like terms)
2x^2 - 34x + 132 = 0 (make it = to 0)
2(x^2 - 17x + 66) = 0 take out gcf
2(x - 11)(x - 6) = 0 factor
x - 11 = 0 or x - 6 = 0
x = 11 or x = 6

answers are (11,6) or (6,11)

Answer 16

Actually is is (11,6) AND (6,11) you are intersecting a circle with a line..

That would be two points.