Question

Someone please help me real quick. Im going to post the question now

Answer 1

given
\[\cos(\sqrt{t})/\sqrt{t}\]
If l let u = sqt(t) then does that mean it applies to both cos funtion and root funtion, or just the inner most sqrt inside cos????????

Answer 2

both..........

Answer 3

that doesnt help me for taking the indefinite integral though

Answer 4

because u have given new value to sqrt (t) no matter where it is

Answer 5

u might need to post your question to have opinions on that problem

Answer 6

\[\int\limits_{}^{}\cos(\sqrt{t})/\sqrt{t}\]

Answer 7

You need to consider
\[\frac{\mathbb{d}u}{\mathbb{d}x} \]

Answer 8

/dt*

Answer 9

try sqrt(t)= z

Answer 10

I was trying to get ride of the root t in the botom with \[dt = 2\sqrt{t} du\]

Answer 11

You need to substitute in u for root t there aswell..

Answer 12

after substituting z=t^1/2 u give get as below
integration sign ( cosz * 2z^2 dt )

Answer 13

then u can use integration by parts keeping z^2 as first term and cosz as second

Answer 14

let me show you what im trying

Answer 15

let u = \[\sqrt{t}\]

then \[du = 1/(2\sqrt{t})dt\]
\[dt = 2\sqrt{t}du\]
then i get
\[\int\limits_{}^{} \cos(u)/u 2\sqrt{t}du\]

Answer 16

is this wrong?

Answer 17

change t^1/2 to u because now we cant have t in new eqation, now we are dealing with u only

Answer 18

oooooooooooo

Answer 19

got it lol

Answer 20

u r on right track ..well done

Answer 21

bang !!! cheers!!! good luck with other problems too !!

Answer 22

thank you so much!

Answer 23

keep up the gud work !!!