Question

how do you find the equation for a graph with x-intercepts of (2,0) and (-6,0) and a maximum point of (-2,4)

Answer 1

thats a quadratic

Answer 2

the most basic approach is to solve for 3 equations with variables of a b and c; using your x and y values as your quadratic constants

Answer 3

or...or factor in the roots

Answer 4

(x-2)(x+6)

Answer 5

C(x^2 +4x -12) is the family of quadratics with these roots

Answer 6

if we complete the square and plug in for the vertex we got it solved

Answer 7

x^2 +4x +4 = 12+4

(x+2)^2 = 16

Answer 8

(-1/4)(x+2)^2 +4 = y might be it

Answer 9

lets check it out :)

Answer 10

-1/4(x^2 +4x-12)

-x^2/4 -x +3

1/2(-1/4) = 1/(-2/4) = 1/(-1/2) = -2 x is good

Answer 11

-1/4(x^2 +4x -12) |x=-2

(-1/4)(4 -8 -12) = -16/-4 = 4

YES

Answer 12

now that I taught mysef something, any questions lol

Answer 13

no

Answer 14

:) good, cause I dont know if I can remember how I did it ;)