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Mathematics 11 Online
OpenStudy (anonymous):

What's the derivative of f(x)= xe^-x^2

OpenStudy (anonymous):

i am pretty sure you can only break that down using ln

OpenStudy (anonymous):

No need to use ln. You have to use the product rule.

OpenStudy (anonymous):

Yes product rule, but is it necessary to do ln AnwarA. I don't think so, it is a form we can handle.

OpenStudy (anonymous):

\[f'(x)=x(-2xe ^{-x^2})+e ^{-x^2}\]

OpenStudy (anonymous):

Simplify, you will get: \[f'(x)=e ^{-x^2}(1-2x^2)\]

OpenStudy (anonymous):

Does that makes sense?

OpenStudy (anonymous):

I"m not sure how you simplified

OpenStudy (anonymous):

Well. I took e^(-x^2) as a common factor, and multiplied (-2x)(x)=-2x^2.

OpenStudy (anonymous):

oh! That makes sense :)

OpenStudy (anonymous):

Are you aware of the product rule? Can you use it?

OpenStudy (anonymous):

Yes. Thanks so much for your help!

OpenStudy (anonymous):

You're most welcome!!

OpenStudy (anonymous):

Have a great day!

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