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What's the derivative of f(x)= xe^-x^2
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i am pretty sure you can only break that down using ln
No need to use ln. You have to use the product rule.
Yes product rule, but is it necessary to do ln AnwarA. I don't think so, it is a form we can handle.
\[f'(x)=x(-2xe ^{-x^2})+e ^{-x^2}\]
Simplify, you will get: \[f'(x)=e ^{-x^2}(1-2x^2)\]
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Does that makes sense?
I"m not sure how you simplified
Well. I took e^(-x^2) as a common factor, and multiplied (-2x)(x)=-2x^2.
oh! That makes sense :)
Are you aware of the product rule? Can you use it?
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Yes. Thanks so much for your help!
You're most welcome!!
Have a great day!
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