Question

how do you solve
2+4x+x square=0
and getting the answers -0.59, -3.41

Answer 1

combine like terms:

2 +4x +x = 0.....x square?

Answer 2

x^2 + 4x + 2 = 0

-2 +- sqrt(2)

Answer 3

yes x square i dont know how to write the little two on the top

Answer 4

the 6 button has a caret if your shift it :)

x^2

Answer 5

ok.. so how do i get the answers -0.59 and -3.41 by doing this equation???

Answer 6

\[x^2+4x+2=0\] is a quadratic equation ( a polynomial of second degree).. The discriminant is \[Δ=4^2-4*1*2=8\] so the roots are
\[x_1=(-4+\sqrt{Δ})/(2*1)=-0.59\]
and
\[x_2=(-4-\sqrt{Δ})/(2*1)=-3.41\]

For more information try:
http://en.wikipedia.org/wiki/Quadratic_equation

Answer 7

I should add that when you have a quadratic equation
\[ax^2+bx+c=0\]
the discriminant is
\[Δ=b^2-4ac\]
and the roots are
\[x1=(-b+\sqrt{Δ})/2a\]
and
\[x2=(-b-\sqrt{Δ})/2a\]