Question

evaluate the following: log5 (1/125)

Answer 1

[ln1/125]/[ln5]=[ln125^(-1)]/[ln5]=[ln5^(-3)]/[ln5] see if that helps

Answer 2

what do we do next

Answer 3

you can bring that -3 down right? does anything cancel?

Answer 4

get rid of the exponent?

Answer 5

oh yes i was rite. um the 5's cancel rite?

Answer 6

so we have -3(ln5)/(ln5)=-3 the ln5 cancels

Answer 7

so where left with -3?

Answer 8

hello?

Answer 9

?

Answer 10

We can write it as
\[\log_{5}1-\log_{5}125 \] .................. (1)
then we know that logarithm of 1 with any base is zero
so the (1) becomes
\[0-\log_{5}125\] ................... (2)
now we can write this as
\[-\log_{5}5^{3}\] ................... (3)
now this becomes
\[-3\times \log_{5}5 \] ................... (4)
and as we know
\[\log_{5}5=1 \] ...................... (5)
so answer is -3

Answer 11

i got the rite answer :) thankyou!

Answer 12

very good thats what we got above

Answer 13

But in more simple way. :)