Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

A university reported that its enrollment increased from 11,778 students in 2005-2006 to 12,196 students in 2006-2007. a. What is the ratio of the number of students in 2006-2007 to the number of students in 2005-2006 b. From your result in part a, determine the growth factor. Write it in decimal form to the nearest thousandth. c. By what percent did the enrollment increase?

OpenStudy (anonymous):

So confused about this

OpenStudy (anonymous):

what is the ratio of 3 to 2?

OpenStudy (anonymous):

Isn't it 1.5?

OpenStudy (anonymous):

yes, thats right. so what is the ratio of 12196 to 11778 students?

OpenStudy (anonymous):

1.035

OpenStudy (anonymous):

there you go. thats your answer

OpenStudy (anonymous):

But then how do you find the growth factor? That's the part I'm not too sure about.

OpenStudy (anonymous):

growth factor is the factor by which the number of students grew in one year. there were 11778 students one year, and there were 12196 students the next year. By what factor did they increase? It is the same as the ratio. the students increased by a factor of 1.035

OpenStudy (anonymous):

ratios are expressed as 3:2. so you should express your ration for the previous problem part a) to 12196:11778

OpenStudy (anonymous):

a:b is a ratio.

OpenStudy (anonymous):

Right. They said to type it as a decimal or a number though. (:

OpenStudy (anonymous):

however, you can represent 10:2 as 5:1 too. so you should factor out the common terms is 12196:11778 and post it as a simpler ratio.

OpenStudy (anonymous):

Thank you so much for your help though. I appreciate it (:

OpenStudy (anonymous):

alright

OpenStudy (gw2011):

a) 12,196/11,778 This is the ratio b) From (a) above, you get 1.035 This is the growth factor c) 12,196 - 11,778 = 418 This is the increase 418/11,778 = 0.035 = 3.5% This is the percent increase

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!