Question

I am really not sure how to simplify this: 2x(3x+4)^4/3+4x^2(3x+4)^1/3?

Answer 1

Are they raised to fractional powers?

Answer 2

For example,\[2x(3x+4)^{4/3}\]

Answer 3

they are raised to fractional powers....I know there has to be someway the (3x+4) comes out. I'm trying to factor it since there are two of the same terms here. So far this is what I have: [2x(3x+4)^1/3](3x+4)^3/3+2x]

Answer 4

Okay...just give me a sec. I'm only 'half' here. You should notice 2x(3x+4)^(1/3) is a common factor.

Answer 5

yeahhh I can see that. Thanks for trying to help though!

Answer 6

\[2x(3x+4)^{4/3}+4x^2(3x+2)^{1/3}=2x(3x+2)^{1/3}[(3x+4)+2x]\]\[=2x(3x+2)^{1/3}(6x+4)=4x(3x+2)^{1/3}(3x+2)=4x(3x+2)^{4/3}\]

Answer 7

Wait...I made a mistake in the last line...

Answer 8

I'll scan in what I wrote. I never translate things onto the site properly :[

Answer 9

THANK YOU SOOO MUCH! I can see how to do it now, thanks again! :)

Answer 10

kk ;]

Answer 11

wait, isn't 3x+2x = 5x?

Answer 12

It is...damn...thanks for picking that up.

Answer 13

heh, np.

Answer 14

Okay...*this* one should be right. Too many distractions going on...

Answer 15

I just realized something...when I wrote the problem where I have 4x^2, the original problem actually has the x^2 separated from the 4. So it actually is:\[2x(3x+4)^4/3+x^2*4(3x+4)^1/3\]

Answer 16

Does this make a difference to the answer...I went ahead and multiplied x^2+4...to make it 4x^2. I hope this doesn't change all the hard work you did, I just realized this though.

Answer 17

no, it doesn't matter. a * b = b * a. in other words, 7 times 9 is the same as 9 times 7 is the same as 63

Answer 18

okay...thanks.

Answer 19

I am getting ready to post a new thread, maybe you can help?

Answer 20

maybe I can. lets see :)