Mathematics
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OpenStudy (anonymous):
25e^0.1x/e^0.1x + 3=10
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OpenStudy (anonymous):
Can you type it out using the equation toolbox? This question is unclear.
OpenStudy (anonymous):
Written as it, it works out to 25+3 = 10 which makes no sense.
OpenStudy (anonymous):
yes, exactly.
OpenStudy (anonymous):
yes exactly u r true
OpenStudy (anonymous):
dhatra aditya its seem to be that u r indian
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OpenStudy (anonymous):
\[25e^0.1x \div e^0.1x +3 = 10\]
OpenStudy (anonymous):
\[\frac{25e^{0.1x}}{e^{0.1x}}+3=10\]Is that what you're saying?
OpenStudy (anonymous):
Yes, sorry
OpenStudy (anonymous):
thats the same as 25 = 7.
OpenStudy (anonymous):
If what I've written is correct, there are no solutions. The statement is false.
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OpenStudy (anonymous):
The 3 is written in the denominator
OpenStudy (anonymous):
AHHHH....
OpenStudy (anonymous):
But you'd have\[\frac{25}{3}=10\]
OpenStudy (anonymous):
Unless it's\[\frac{25e^{0.1x}}{e^{0.1x}+3}=10\]
OpenStudy (anonymous):
Is that what you mean ^^ ?
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OpenStudy (anonymous):
yes, that
OpenStudy (anonymous):
Okay...
OpenStudy (anonymous):
Multiply both sides by\[e^{0.1x}+3\]to obtain\[25e^{0.1x}=10(e^{0.1x}+3)=10e^{0.1x}+30\]
OpenStudy (anonymous):
Subtract 10e^(0.1x) from both sides to get\[15e^{0.1x}=30 \rightarrow e^{0.1x}=2\]
OpenStudy (anonymous):
Now take the natural logarithm of both sides:\[\ln e^{0.1x}=\ln 2 \rightarrow 0.1x=\ln 2\]Multiply both sides by 10 to give,\[x=10\ln 2\]
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OpenStudy (anonymous):
hello