Question

(a + 1 - 6/a) / (a - 1 - 2/a) simplify

Answer 1

lol...isnt it a^2+a-6/a^2-a-2

Answer 2

\[\frac{1-\frac{6}{a}+a}{-1-\frac{2}{a}+a} \]
Is this the problem expression?

Answer 3

yes only with terms rearranged

Answer 4

Combine the terms in the Numerator and the Denominator into one fraction respectively.
\[\frac{\frac{-6+a+a^2}{a}}{\frac{-2-a+a^2}{a}} \]
Invert the denominator and multiply the result by the Numerator.
\[\frac{-6+a+a^2}{-2-a+a^2} \]
Both the Numerator and Denominator can be factored.
\[\frac{((-2+a) (3+a))}{((-2+a) (1+a))} \]\[\frac{3+a}{1+a} \]

Using Mathematica for the symbol manipulation and that is why the term ordering does't look right.

Answer 5

ok
out casgirl

Answer 6

outcastgirl