[y^2-2y/y^2+7y-18] X [y^2-81/y^2-11y+18] Simplify the rational expression.
break the denominators off into factored squares, and cancel terms to simplify.
i did that and got y(y-9)/(x-2) (y+2)
polpak will help you out
\[\frac{y(y - 2)}{(y+9)(y-2)} * \frac{(y+9)(y-9)}{(y+9)(y+2)} \]
oh wait a sec.....on the bottom right i put (y-2) (y+2) for some reason. the rest i got right though.
hold on let me try this to see if i get it right
Leaves \[\frac{y(y+9)}{(y+9)(y+2)} = \frac{y(y-9)}{(y+9)(y+2)}\]
Ok
polpak is riqht but i think u still have to cancel the terms
he did
ohhh yeah he did... i didnt see the equals siqn... sorry! :))
[y^2-2y/y^2+7y-18] factor you get [y(y-2)/(y-2)(y+9)]cancel you get y/(y+9) [y^2-81/y^2-11y+18] factor you get [(y+9)(y-9)]/[(y-2)(y-9)] cancel you get (y+9)/(y-2) now you can time; [y/(y+9)]*[(y+9)/(y-2)] [y^2+9y)]*[(y^2+7y-14)] from here can you do your own?
would you get rid of y-2??? cuz thats the only way im getting the y(y+9)
you foil
time
[y/(y+9)]*[(y+9)/(y-2)] sorry time not divi [y/(y+9)]*[(y+9)*(y-2)]
Whoops, was that a -11 in the denominator of the second fraction?
My font makes it hard to read those sometimes. Lets try this again.
okay :D ha.
srry I wrong again,it hard to tye ,easy for me to write
\[\frac{y^2-2y}{y^2+7y-18} \times \frac{y^2-81}{y^2-11y+18}\] \[ = \frac{y(y-2)}{(y+9)(y-2)} \times \frac{(y+9)(y-9)}{(y-9)(y-2)}\] \[ = \frac{y}{(y+9)} \times \frac{(y+9)}{(y-2)}\] \[ = \frac{y(y+9)}{(y+9)(y-2)} \] \[= \frac{y}{y-2}\]
[y^2+9y)]*[(y^2+7y-14)]not this [y^2+9y)]*[(y^2+7y-18)] this correct
While that's correct, yours can be simplified further Nancy.
Well correct assuming that by * you mean / that is.
ha okay thanks polpak and nancy i really appreciate your help!
Did you follow all that Carr?
The best strategy to use with these is to leave them factored as long as possible so you can quickly see what cancels.
yeah i got a little head of my self and put the wrong number but thank you both!
That's ok, I misread a negative so we all make mistakes ;)
yes still time (y/y-2)*(y+9)(y-2)*[y^2-81/y^2-11y+18]
from here are you OK to do your own? [y^2+9y)]*[(y^2+7y-18)]
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