Question

another one

Answer 1

that last page was making my browser laggy

Answer 2

sorry:S

Answer 3

soo?:)

Answer 4

trying to figure out a clever way to do it so I don't have to do all that multiplication

Answer 5

well I know that A^2n = I
and A^2n+1 = A
from my matrix calculator

Answer 6

so the solution and the steps is A^2n = I
and A^2n+1 = A only??

Answer 7

yeah, but you are going to need to show how you got that

Answer 8

yeah actually:S:S sorry

Answer 9

okay:
for the muliplication on the diagonal we get: (1/2)^2 + (-1/2)^2 + (-1/2)^2 + (-1/2)^2 = 1

Answer 10

for not on the diagonal we get: 1/2*-1/2 + 1/2*-1/2 + 1/2*1/2 + 1/2*1/2 = 0

Answer 11

see I did part a but the problem in part B

Answer 12

So A^2 = identity matrix
then A^3 = A^2 * A = Identity * A = A

Answer 13

well then for A^2m it's just (A^2)^n which is just multiplying an Identity matrix a bunch of times

Answer 14

for A^2n+1 = A^2n * A = (A^2)^n * A = A

Answer 15

thats all?

Answer 16

yep A^2n = (A^2)^n = Id^n = Id
A^2n+1 = (A^2)^n * A= Id * A = A

Answer 17

thanks:)

Answer 18

find conditions on a and b such that the following system of linear equations has
a no solution
b unique solution or
c infinitely solution
x+y+3z=2
x+2y+4z=3
x+3y+az=b

Answer 19

hmm

Answer 20

sorry Iam making u tired :)

Answer 21

not sure how to effectively do that one.