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Determine a. if f has a maximum value or a minimum value; b. the value of x at which the maximum or minimum occurs; c. the maximum or minimum value of f: f(x)=2x^2+3x+2
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since the coefficient of x^2 is postive then the parabola opens upward so U that means we have a minmum
Oh, wow, now that made sense...so the first part is that easy..okay, i'm following thoroughly
f(x)=2(x^2+3x/2)+2 f(x)=2(x^2+3x/2+(3/4)^2)+2-2(3/4)^2 f(x)=2(x+3/4)^2+2-9/8 f(x)=2(x+3/4)^2+7/8 so the max is x=-3/4 the max value is 7/8
wow...that made sense...not too bad actually
lol usually people get confused when I add in a weird zero
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I didn't see a weird 0
lol..thanks again
ur wecolme
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