Evaluate the integral by completing the square and using trig substitution. After completing the square I got (x+3)^2-3 but I don't know what to do next

Question

yuki · Answer

you have to give us what we are supposed to integrate

is it
$$\int\limits[(x+3)^2-2]dx$$?

anonymous · Answer

no, its unlikely to be that ^ lol

it will be something with a division.

my guess is :

$$1/ [ (x+3)^2 -3] $$

anonymous · Answer

or possibly the above with a sqrt on the denominator, its a standard integral

cherrilyn · Answer

$$\int\limits_{}^{} dx \div (x ^{2} + 6x + 6 )^{2}$$

cherrilyn · Answer

oh no... Sorry.. the equation is

$$\int\limits_{}^{} dx / (x ^{2} + 6x + 6)^{2} $$