Question

find integral of {ln(x)^3/x dx

Answer 1

let u=ln(x)

Answer 2

provided you mean

\[[ \ln(x)]^3 / x\]

Answer 3

u=ln(x)
du= (1/x) dx

integral = u^3 du = u^4 / 4 +C

= [ ln(x)]^4 +C

Answer 4

Just as elec said :) let u = ln(x) then du = 1/x and you'll get the following:

\[=\int\limits u^3 du \]\[= \frac{u^4}{4} + c \rightarrow = \frac{(\ln|x|)^4}{4} + c\]

Answer 5

EDIT: (1/4) [ ln(x)]^4 +C

Answer 6

LOL! :)