Question

If you graph f(x)= x^2 + y^2 then it is a circle but then how would you graph the square root of f(x)?

Answer 1

how would you go about graphing it*

Answer 2

but f(x)= x^2 + y^2 isn't a circle

Answer 3

i'm pretty sure f(x)= x^2 + y^2 is a circle...
the square root of f(x) is half a circle
if it's positive sqrt of f(x), it'll be the top half of the circle
if it's negative, it will be the bottom half.

Answer 4

what would be the radius?

Answer 5

good point, i didn't catch that
uzma right
but i think the point of the question is to understand that the square roots is half a circle
so you need a value for f(x), otherwise, as uzma said, it's not a circle

Answer 6

yes :)

Answer 7

it must be x^2 + y^2= costant, then centre is (0,0) and radius is sqrt(constant)

Answer 8

or we can have the general eq
x^2 +y^2 +2fx+2gy +c=0