Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

Find the definite integral using the Fundamental Theorem of Calculus.

OpenStudy (anonymous):

\[\int\limits_{-1}^{1} e^-x (4-e^x) dx\]

OpenStudy (anonymous):

see the thing is iruno how to break this ice

OpenStudy (anonymous):

is exactly what i need help with

OpenStudy (anonymous):

That's e^(-x) by the way And I know, I'm so lost.

OpenStudy (anonymous):

haha yeh this crap makes people lost in formulas man

OpenStudy (anonymous):

so define the fundamental thrm of calculus; then see how that applies :)

OpenStudy (anonymous):

My real question is, I don't know where to start with this problem.

OpenStudy (anonymous):

start by defining the FTC and see how it applies lol.... that is the start

OpenStudy (anonymous):

That does nothing for me.

OpenStudy (dumbcow):

expand it and you will get 4e^-x - 1

OpenStudy (anonymous):

Yes, what dumbcow said. Then you can take the integral of each part.

OpenStudy (anonymous):

FTC simply says it CAN be done; then you apply the techniques :)

OpenStudy (anonymous):

I don't know how to apply the techniques haha, that's why I'm here!

OpenStudy (anonymous):

the equation editor seems to have distorted the equation ; can you verify it?

OpenStudy (anonymous):

I was given a take-home test, and I'm supposed to teach myself definite integrals and have it due tomorrow.

OpenStudy (dumbcow):

FTC says the definite integral = F(1) - F(-1) but you have to find F(x) by taking anti-derivative of f(x)

OpenStudy (anonymous):

\[\int\limits_{-1}^{1} 1/(e^x) (4-e^x) dx\]

OpenStudy (anonymous):

If you integrate 4e^-x, you would get -4e^-x. Then, integrate 1 and you get x So then you have -4e^-x - x evaluated from -1 to 1

OpenStudy (anonymous):

\[\int\limits_{-1}^{1} \frac{1}{e^x} (4-e^x) dx\]

OpenStudy (anonymous):

^^ that

OpenStudy (anonymous):

frac{top}{bottom} in the editor makes for fancy fractions :)

OpenStudy (anonymous):

Ooo, ok!

OpenStudy (anonymous):

integrate {4/(e^x) - 1} dx

OpenStudy (anonymous):

4 (ln(e^x)) - x

OpenStudy (dumbcow):

do what math93 said

OpenStudy (anonymous):

4x-x = 3x F(x) = 3x right?

OpenStudy (dumbcow):

no F(x) =-4e^-x - x

OpenStudy (anonymous):

close lol

OpenStudy (anonymous):

\[ \frac{-4}{e ^{x}}-x\] evaluated from -1 to 1

OpenStudy (anonymous):

coulda thunked that 1/u integrates to ln(u)....

OpenStudy (anonymous):

4e^-x is just as good i spose :)

OpenStudy (anonymous):

if you sub in your values, you get (-4e^-1 - 1)-(-4e^-1+1)

OpenStudy (anonymous):

i see it..... just blind in my old age

OpenStudy (anonymous):

After the values are substituted in, do I just simplify?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

So is the final answer (-2)?

OpenStudy (anonymous):

Yeah, that's what I got

OpenStudy (anonymous):

So is the answer just (-2) by itself? Or is there anything on the opposite side of the equal sign?

OpenStudy (anonymous):

the integral of the original problem = -2, so "-2" is the final answer

OpenStudy (anonymous):

Alright, I appreciate the help, I'll use this one as an example to hopefully finish the rest of the problems I have, cheers!

OpenStudy (anonymous):

Good luck!

OpenStudy (anonymous):

Thank you!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!