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How to find the volume of a cube using spherical triple integral?
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\[\int\limits_{\theta = 0}^{2\pi}\int\limits_{\psi = 0}^{\pi}\int\limits_{\rho = 0}^{r}1d \rho d \psi d \theta\]
solve and you'll get the (4/3)pi * r^3
thanks
thats for a sphere, not a cube??
:x i could have sworn i read sphere....
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tripleintegral, what i did was completely wrong! ....and i honestly have no idea why you would want to do a cube in spherical coordinates..
thanks anyway....
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