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Mathematics 14 Online
OpenStudy (anonymous):

∫[x(3x^2-2)^10,x]

OpenStudy (anonymous):

Anyone?

OpenStudy (anonymous):

After 10 there is a comma x what is that?

OpenStudy (anonymous):

its the integral with respect to x the , x is the Dx

OpenStudy (anonymous):

Are you familiar with u sub?

OpenStudy (anonymous):

yes i subed and got ( 3x^2-2)^10/66)

OpenStudy (anonymous):

but it doesnt look right i think

OpenStudy (anonymous):

I don't know how you would get that, but for your u -- your the derivative of your u should be available in the question. And u is usually in the bracket or under the radical or in the denominator something like that.

OpenStudy (anonymous):

( 3x^2-2)^11)/(66) *

OpenStudy (anonymous):

or ( u)^11/66) without re subing

OpenStudy (anonymous):

Oh yeah, I wasn't looking that far ahead.

OpenStudy (anonymous):

\[\int\limits x(3x^2-2)^{10}dx \rightarrow u=3x^2-2, du=6xdx, \frac{du}{6x}=dx\] \[\int\limits \frac{x(u)^{10}}{6x}du \rightarrow \frac{1}{6} \int\limits (u)^{10}du \rightarrow \frac{1}{66} u^{11}+c \rightarrow \frac{1}{66} (3x^2-2)^{11}+c\]

OpenStudy (anonymous):

coo then its right then

OpenStudy (anonymous):

thank you both

OpenStudy (anonymous):

sure thing

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