Question

18
(sigma)(-1)^n2n
n=4

Answer 1

\[\sum_{n=4}^{18}-1^{n^2n}\] ?? is this the question?

Answer 2

yes

Answer 3

actually its( -1^n) 2n

Answer 4

oh well since it is negative one you know that it will either be 1 or negative 1 for each n in the middle of the paratheses, however since you have a 2n on the outside as an exponent that means that it will always be an even exponent so each time, the answer will be 1. so just go (18 - 4)(1) = 14

Answer 5

my directions tell me to use a graphing calculator but i have no idea how to put sigma into a calculator?