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Mathematics 20 Online
OpenStudy (anonymous):

A ball of radius 11 has a round hole of radius 7 drilled through its center. Find the volume of the resulting solid.

OpenStudy (anonymous):

Find the volume of the ball and then subtract the volume of the hole.

OpenStudy (anonymous):

that is what i have been trying. a ball is a sphere so v= 4/3r^3 and the hole is a cylinder pi*r^2*h but what is h the height it isnt the diameter of the sphere

OpenStudy (anonymous):

The height is the the radius of the ball times 2 (Diameter) :)

OpenStudy (anonymous):

a cylindrical hole would be slightly shorter than the diameter of the sphere the thing is idk how to find that

OpenStudy (anonymous):

If you are going to picture this out in your mind, or better yet, get a pen and paper and draw it.. You will find out that it is the height of sphere. Operative word is "center of the ball".

OpenStudy (anonymous):

i did do that and i believe it was the diameter, but after some rethinking, as well as the answer being wrong i saw a different picture. Imagine a sphere. it is round obviously if you drill a hole threw it the the whole will be a cylinder. Cylinders have flat bases. A flat base would mean it cuts off before the end of the sphere. if the height was the diameter it would mean that the base is curved

OpenStudy (anonymous):

afs brings a good point did you learn triple/double integrals yet? i believe that that is the only way to get the answer

OpenStudy (anonymous):

Oh yeah! Figured that one out thanks for the clear description. @_@

OpenStudy (anonymous):

We are at area between curves and volume between curves. i kind of know how to do those, but this, which is one of them, doesn't give all the info, all i need is the height and im good but dont know the height. :( @ mcometa :D

OpenStudy (anonymous):

i think you can do this using what you do do you know the washer method yet?

OpenStudy (anonymous):

i zoned out for that one, im using the shell method, but i dont know how exactly to apply it to this

OpenStudy (anonymous):

ehh...i'm not sure what the shell method is LOL but the washer method is bascially integral curve1-curve2

OpenStudy (anonymous):

Are you doing this in polar? or spherical?

OpenStudy (anonymous):

And is this calc 3 or calc 2

OpenStudy (anonymous):

so now imagine your cylinder and sphere on the xy plane ONLY the xy plane you'll see a circle and a rectangle curve1 will be the circle and curve2 will be the rectangle apply washer. this should work.

OpenStudy (anonymous):

so the equation for the volume of a sphere - the volume of a cylinder? and @ polpak ? oh and calc 2

OpenStudy (anonymous):

no

OpenStudy (anonymous):

did what i just wrote make any sense?

OpenStudy (anonymous):

lol i typed that before reading urs and yes it did i'll go ahead and try that ty :D

OpenStudy (anonymous):

okay good luck rotate about y axis! cheers!

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