Question

need help finding the solution(s) to this equation..

Answer 1

\[y ^{-1}-22^{-1 \over 2}+120=0\]

Answer 2

1/y -(sqrt[22])+120 = 0
y = 1/(sqrt[22]-120)

Answer 3

wrong

1/y -(1/(sqrt[22]))+120 = 0
1/y = (1/(sqrt(22) - 120) = (1-120*sqrt[22])/sqrt[22])
y = sqrt[22]/(1-120sqrt[22])

Answer 4

wait, so the first thing you wrote is wrong. But this second one is right?

Answer 5

yep

Answer 6

oh ok, so there is only one answer? \[\sqrt{22}\over 1-120\sqrt{22}\] is this correct?

Answer 7

the line didn't show up but it's supposed to be a fraction

Answer 8

he left :(. Polpak, does that look correct to you?

Answer 9

Sorry, one sec

Answer 10

\[\frac{1}{y} - \frac{1}{\sqrt{22}} + 120 = 0\]
\[\implies \frac{1}{y} = \frac{1}{\sqrt{22}} - 120\]
\[\implies \frac{1}{y} = \frac{1}{\sqrt{22}} - \frac{120\sqrt{22}}{\sqrt{22}}\]
\[\implies \frac{1}{y} = \frac{1-120\sqrt{22}}{\sqrt{22}}\]
\[\implies y =\frac{\sqrt{22}}{1-120\sqrt{22}} \]

Answer 11

Yeah, that's correct

Answer 12

can i get some help again please..

Answer 13

the root 22 on the bottom part wouldn't type in my online assignment.. so it must not be there..

Answer 14

Are you certain the original equation is correct?

Answer 15

i will double check.

Answer 16

wow. I don't know why i keep doing that..but I forgot the y.. it is all the same except there is a y after the 22

Answer 17

\[y ^{-1}-22y ^{-1 \over 2}+120=0\]

Answer 18

sorry!!

Answer 19

Ah, that's nicer certainly.