Mathematics
7 Online
OpenStudy (anonymous):
need help finding the solution(s) to this equation..
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OpenStudy (anonymous):
\[y ^{-1}-22y ^{-1 \over 2}+120=0\]
myininaya (myininaya):
let u=y^(-1/2)
myininaya (myininaya):
so what does u^2=?
OpenStudy (anonymous):
x?
myininaya (myininaya):
u^2=y^(-1)
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OpenStudy (anonymous):
ok, thanks. so where do I go from here?
myininaya (myininaya):
do you know how to factor u^2-22u+120=0
OpenStudy (anonymous):
i'm trying to figure out what works for 22 and 120..does anything besides 2 go into them both?
myininaya (myininaya):
(u-10)(u-12)=0
OpenStudy (anonymous):
so will the 2 solutions be positive 10 and 12 then?
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myininaya (myininaya):
y^(-1/2)=10
y^(-1/2)=12
since u=y^(-1/2)
myininaya (myininaya):
solve for y from both of these equations and you are done
OpenStudy (anonymous):
would it be 10 1/2 and 12 1/2 then? i didn't know the solutions could be anything besides a whole numbers
myininaya (myininaya):
y=10^(-2)
y=12^(-2)
you can evaluate those
OpenStudy (anonymous):
Sorry I have so many questions..I just want to make sure I understand completely. To evaluate these what exactly do i do?
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myininaya (myininaya):
do you know law of exponents?
OpenStudy (anonymous):
possibly. I'm not sure exactly what that entails. I don't know the tnames for all these math terms
myininaya (myininaya):
y=10^(-2)=1/(10^2)
y=12^(-2)=1/(12^2)
can you evaluate it now?
OpenStudy (anonymous):
do they just end up being 10 and 12?
myininaya (myininaya):
y=1/(10*10)
y=1/(12*12)
can you evaluate these now?
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OpenStudy (anonymous):
100 and 144?
OpenStudy (anonymous):
I just didn't think it would be that large of number.
myininaya (myininaya):
y=1/100
y=1/144
myininaya (myininaya):
you can plug these in to check if you want
OpenStudy (anonymous):
oh the 1 does stay on top? wasn't sure about that. Sorry i'm so incompetent at math.
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OpenStudy (anonymous):
Ok will do. thanks
myininaya (myininaya):
np how about a medal? lol
OpenStudy (anonymous):
i'd say you earned it!
myininaya (myininaya):
yay! :)
myininaya (myininaya):
thanks you i will give you one too
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OpenStudy (anonymous):
yay! Idk if i deserve one but thanks anyways! :)
myininaya (myininaya):
lol ok deserve it here if we have the function f(n)=2
find f(3)=...
OpenStudy (anonymous):
2..or n...er.. uhh
myininaya (myininaya):
lol thats right
OpenStudy (anonymous):
woohoo!
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myininaya (myininaya):
the 2 is right
myininaya (myininaya):
its a horizontal line going through the y axis at 2 so no matter what you plug in fir x (or n) you will always get 2
myininaya (myininaya):
have a goodnight