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Mathematics 7 Online
OpenStudy (anonymous):

need help finding the solution(s) to this equation..

OpenStudy (anonymous):

\[y ^{-1}-22y ^{-1 \over 2}+120=0\]

myininaya (myininaya):

let u=y^(-1/2)

myininaya (myininaya):

so what does u^2=?

OpenStudy (anonymous):

x?

myininaya (myininaya):

u^2=y^(-1)

OpenStudy (anonymous):

ok, thanks. so where do I go from here?

myininaya (myininaya):

do you know how to factor u^2-22u+120=0

OpenStudy (anonymous):

i'm trying to figure out what works for 22 and 120..does anything besides 2 go into them both?

myininaya (myininaya):

(u-10)(u-12)=0

OpenStudy (anonymous):

so will the 2 solutions be positive 10 and 12 then?

myininaya (myininaya):

y^(-1/2)=10 y^(-1/2)=12 since u=y^(-1/2)

myininaya (myininaya):

solve for y from both of these equations and you are done

OpenStudy (anonymous):

would it be 10 1/2 and 12 1/2 then? i didn't know the solutions could be anything besides a whole numbers

myininaya (myininaya):

y=10^(-2) y=12^(-2) you can evaluate those

OpenStudy (anonymous):

Sorry I have so many questions..I just want to make sure I understand completely. To evaluate these what exactly do i do?

myininaya (myininaya):

do you know law of exponents?

OpenStudy (anonymous):

possibly. I'm not sure exactly what that entails. I don't know the tnames for all these math terms

myininaya (myininaya):

y=10^(-2)=1/(10^2) y=12^(-2)=1/(12^2) can you evaluate it now?

OpenStudy (anonymous):

do they just end up being 10 and 12?

myininaya (myininaya):

y=1/(10*10) y=1/(12*12) can you evaluate these now?

OpenStudy (anonymous):

100 and 144?

OpenStudy (anonymous):

I just didn't think it would be that large of number.

myininaya (myininaya):

y=1/100 y=1/144

myininaya (myininaya):

you can plug these in to check if you want

OpenStudy (anonymous):

oh the 1 does stay on top? wasn't sure about that. Sorry i'm so incompetent at math.

OpenStudy (anonymous):

Ok will do. thanks

myininaya (myininaya):

np how about a medal? lol

OpenStudy (anonymous):

i'd say you earned it!

myininaya (myininaya):

yay! :)

myininaya (myininaya):

thanks you i will give you one too

OpenStudy (anonymous):

yay! Idk if i deserve one but thanks anyways! :)

myininaya (myininaya):

lol ok deserve it here if we have the function f(n)=2 find f(3)=...

OpenStudy (anonymous):

2..or n...er.. uhh

myininaya (myininaya):

lol thats right

OpenStudy (anonymous):

woohoo!

myininaya (myininaya):

the 2 is right

myininaya (myininaya):

its a horizontal line going through the y axis at 2 so no matter what you plug in fir x (or n) you will always get 2

myininaya (myininaya):

have a goodnight

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