Question

7 over 5x squared -20x+20
plus
1 over 20x squared - 80

Answer 1

lol, the question is not clear >_<

Answer 2

7 over 5x squared minus 20x plus 20 add to 1 over 20x squared minus 80

Answer 3

i agree with sstarica
because 7over 5x or 7over5 then an x ?

Answer 4

\[\frac{7}{5x^2} - 20x + 20 + \frac{1}{20x^2} - 80\]?

Answer 5

______7_____
5x squared -20x+20 added to 1 over 20x squared - 80

Answer 6

so is sstarica right?

Answer 7

sorry for the confusion Ihavent quited figured out how to work this program yet

Answer 8

\[\frac{7}{5x^2-20x+20} + \frac{1}{20x-80}\]

Answer 9

yes

Answer 10

alright lol :)

Answer 11

how do you get horizontal bars for the fractions with the maths editor

Answer 12

frac{a}{b} <-- ^_^

Answer 13

\[\frac{7}{5(x-4)^2} + \frac{1}{20(x-4)}\]\[\frac{7}{5(x^2-4x+4)} + \frac{1}{20(x-4)}\]

Answer 14

wrong order
lol

Answer 15

lol, I noticed

Answer 16

multiply top and bottom of second by x-4

Answer 17

it's actually (x-2)^2 :)

Answer 18

nvm LOL, I wrote the wrong question

Answer 19

yeh something like that , im going to go to sleep soon

Answer 20

no, wait, I wrote the right question >_<

Answer 21

(x-2)^2 ^_^" instead of (x-4)^2

Answer 22

its 1.40 in the morning where I am , I am too generous staying up this late to help ppls lol

Answer 23

lol, go to bed

Answer 24

\[= \frac{7(4)(x-4) + (x-2)(x-2)}{20(x-2)^2(x-4)}\]
\[= \frac{28x - 112 +x^2 - 4x -4}{20(x-2)^2(x-4)}\]
\[= \frac{x^2 + 24x -116}{20(x-2)^2(x-4)}\]

hmm, there's something wrong

Answer 25

I'm not sure

Answer 26

did you understand what I just did?

Answer 27

not really i'm not very smart with algebra

Answer 28

I factored, then put both fractions with the same denominator to have them in one :)

Answer 29

write down the steps on paper, and you'll figure out what I did ^_^

Answer 30

wait a min, there's a mistake in the last 2 steps, hold on dear ^_^

Answer 31

I'm lost because under the 1 in 20x squared minues 80

Answer 32

\[= \frac{28x-112+x2-4x+4}{20(x-2)^2(x-4)}\]<-- for the second line

Answer 33

I factored, I pulled out 20 as a common factor and was left with (x-4) use the distributive law to check ^_^

Answer 34

\[= \frac{x^2+24x-108}{20(x-2)^2(x-4)}\]

Answer 35

sorry about the mess, but are you following now :)?

Answer 36

i think so, thank you so much

Answer 37

np ^_^, but there's still something fishy about it lol, I can't seem to factor the numerator

Answer 38

does the question want you to add only? or simplify?

Answer 39

simplify

Answer 40

hmm

Answer 41

I'm sure of the following steps I just made, but looks it can't be factored

Answer 42

thank you