Question

Solve each problem by using the quadratic formula. Write solutions in simplest radical form.

2x^2 + 2x- 1 = 0

Answer 1

so ax^2 + bx + c = 0

Answer 2

\[(-b \pm \sqrt{b^2 - 4 a c}) /2a\]

Answer 3

just plug in the values your equation is 2x^2 + 2x - 1 = 0
ax^2 + bx + c = 0

Answer 4

tell me what a = , b = , and c =

Answer 5

are they a=2 b=2 c= -1 ?

Answer 6

perfect now plug them into the quadratic equaiton

Answer 7

and you must rememeber the pm

Answer 8

pm -> plus and minus

Answer 9

because you will have two solutions one for a positive square root, and one for a negative square root

Answer 10

\[-2\pm \sqrt{12} /4\] this is what im getting so far am i on the right track

Answer 11

yeah. see that plus and minus you have to look at it like this

-2 + sqrt(12)/4 and -2 - sqrt(12)/4

Answer 12

so you will get two answers

Answer 13

would the first answer be 1 and the second answer be -2

Answer 14

you will get -1 +- sqrt(3)/2

Answer 15

i have to go

Answer 16

you will get -1 +- sqrt(3)/2