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OpenStudy (anonymous):
What is the area between the curves
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OpenStudy (anonymous):
x = y^{2} - 9
OpenStudy (anonymous):
\[x = y^{2} - 9\]
OpenStudy (anonymous):
and
OpenStudy (anonymous):
\[x = -y^{2} + 9\]
OpenStudy (anonymous):
Hope someone can help me out!!
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OpenStudy (amistre64):
is there a bounds set or do we determine the bounds by the intersecting curves?
OpenStudy (anonymous):
no bounds set
OpenStudy (amistre64):
without set bounds, we should assume that it is the intersection of the two curves
OpenStudy (anonymous):
correct
OpenStudy (anonymous):
I set the 2 equal to each other and set it equal to 0
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OpenStudy (amistre64):
it looks likethis :)
OpenStudy (amistre64):
if we can find the area of half of one of them, we can just multiply by 4 to get the total
OpenStudy (amistre64):
lets use y^2 - 9 since it is a difference of squares:
the roots are x=3 and x=-3
OpenStudy (amistre64):
y=....yeah
OpenStudy (amistre64):
so our bounds to find the area should be between 0 and 3; and we can equate this to x^2 - 9 and be none the worse
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OpenStudy (amistre64):
x^2 - 9 integrates up to (x^3/3) -9x
at 0 we get a value of zero so thats pointless; use 3
OpenStudy (amistre64):
333
--- - 27
3
9 - 27 = |-18|; one quareter of this is equal to 18
18*4 = 40 + 32 = 72
OpenStudy (anonymous):
Fantastic!!! I did that problem completely wrong! Thank you again!! Medal for you - hehe
OpenStudy (amistre64):
should look like this :)
OpenStudy (amistre64):
question is; am I right? or does everything cancel to zero :)
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