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Mathematics 8 Online
OpenStudy (anonymous):

What is the area between the curves

OpenStudy (anonymous):

x = y^{2} - 9

OpenStudy (anonymous):

\[x = y^{2} - 9\]

OpenStudy (anonymous):

and

OpenStudy (anonymous):

\[x = -y^{2} + 9\]

OpenStudy (anonymous):

Hope someone can help me out!!

OpenStudy (amistre64):

is there a bounds set or do we determine the bounds by the intersecting curves?

OpenStudy (anonymous):

no bounds set

OpenStudy (amistre64):

without set bounds, we should assume that it is the intersection of the two curves

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

I set the 2 equal to each other and set it equal to 0

OpenStudy (amistre64):

it looks likethis :)

OpenStudy (amistre64):

if we can find the area of half of one of them, we can just multiply by 4 to get the total

OpenStudy (amistre64):

lets use y^2 - 9 since it is a difference of squares: the roots are x=3 and x=-3

OpenStudy (amistre64):

y=....yeah

OpenStudy (amistre64):

so our bounds to find the area should be between 0 and 3; and we can equate this to x^2 - 9 and be none the worse

OpenStudy (amistre64):

x^2 - 9 integrates up to (x^3/3) -9x at 0 we get a value of zero so thats pointless; use 3

OpenStudy (amistre64):

333 --- - 27 3 9 - 27 = |-18|; one quareter of this is equal to 18 18*4 = 40 + 32 = 72

OpenStudy (anonymous):

Fantastic!!! I did that problem completely wrong! Thank you again!! Medal for you - hehe

OpenStudy (amistre64):

should look like this :)

OpenStudy (amistre64):

question is; am I right? or does everything cancel to zero :)

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