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Indefinite Integral:
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\[\int\limits_{?}^{?} e ^{x} + 4xe ^{2x} / xe ^{x} dx\]
you must specify a bit more is it \[\frac {(e^x + 4xe ^{2x} ) } { xe^x} \] or \[e^x +\frac{ [ 4xe ^{2x}] } {xe^x} \]
either way it will involve you cancelling factors of e^(x) [ remember that e^(2x) =[ e^(x) ]^2
if its the first one then you get \[\frac{1}{x} + 4e^x\] which can be integrated easily as ln|x| +4e^x +C
if its the second one then you will get e^x +4e^x = 5e^x which integrates as 5e^x +C
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