What it says is: Determine the x-coordinates of the points of inflection for the graph of f(x). so I took the derivative of f(x)=9e and I got 0, how am I supposed to get a point of inflection from this?
wait, i forgot to say something, I know that the point of inflection is the derivative of the function twice, and that is what 9e is, I had already taken the derivative once. :)
For inflection points you want to see when the curvature changes. That means that the second derivative changes sign.
Yep, but there is no x to set equal to x, sooo what do I do?
x=0, sorry typoo
What was the original function
f(x)=3xe^(-x^2)
And you got 9e when you took the derivative?
Yep
That's unpossible
omg. omg. I realized what i did wrong. thank you
the i plugged in 1 for x for some odd, odd, odd reason.
If the derivative were 9e, then I should be able to integrate 9e and get back to the original function plus a constant. But the integral of 9e is 9ex
which is not the function
lol exactly. :) ha thank you!
=)
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