How do you write r=2sintheta and r=2sin2theta into polar coordinates?
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OpenStudy (anonymous):
it is polar coordinates
OpenStudy (anonymous):
r = 2 sin theta, theta is theta
OpenStudy (anonymous):
maybe you mean cartesian coordinates?
OpenStudy (anonymous):
it says solve the system of equations on the polar plane: then it has those two equations. And says Write your solutions as polar coordinates [hint there are 4]
OpenStudy (anonymous):
oh
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OpenStudy (anonymous):
yeah ha. Do you know anyone who could help?
OpenStudy (anonymous):
yes me, give me medal
OpenStudy (anonymous):
I don't know how to?
OpenStudy (anonymous):
i just gave you medal
OpenStudy (anonymous):
but how
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OpenStudy (anonymous):
i took it away your medal
OpenStudy (anonymous):
solve 2 sin t = 2 sin (2t)
OpenStudy (anonymous):
Ah, it's already in polar coordinates. (r, theta)
OpenStudy (anonymous):
assume that r1 = r2 , where r1 = 2 sin t , and r2 = 2 sin (2t)
OpenStudy (anonymous):
2 sin t = 2 ( 2 sin t cos t )
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OpenStudy (anonymous):
woah slow down haha
OpenStudy (anonymous):
2sin t - 4sint*cost = 0
OpenStudy (anonymous):
more medals
OpenStudy (anonymous):
2sin t ( 1 - 2 cos t ) = 0
OpenStudy (anonymous):
how is that four solutions
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OpenStudy (anonymous):
solve
OpenStudy (anonymous):
solve
OpenStudy (anonymous):
solve what?
OpenStudy (anonymous):
2sin t = 0 or 1- cos t = 0
OpenStudy (anonymous):
helppppp
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OpenStudy (anonymous):
sin t = 0 when t = 0, pi ,
OpenStudy (anonymous):
1- 2 cos t = 0 when cos t = 1/2 , when t = pi/3, 5pi/3
OpenStudy (anonymous):
so the solutions are t = { 0, pi, pi/3, 5pi/3}
OpenStudy (anonymous):
how do i show the work? what do I write for the equations and what answer goes with which one
OpenStudy (anonymous):
Did you use the right equations? 2sint and 2sin2t
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