Question

ok how to find the area ??

Answer 1

integrate :) the trick is, does your material say to keep (-) areas negative or not....

Answer 2

ok i did that

Answer 3

but i get confuse what points show i use

Answer 4

\[F(x) = \int\limits_{0}^{3} (x^3 -4x) dx \rightarrow F(x)=\frac{x^4}{4} - \frac{4x^2}{2} |_{0}^{3}\]

Answer 5

ok

Answer 6

Area = F(3) - F(0)

F(0) = 0

F(3) = 81/4 - 36

Answer 7

22'3/4 - 36 = -13' 1/4..... so that should be the area

Answer 8

it aint cause I forgot how to multiply lol

Answer 9

(3)^4
---- - 2(3)^2
4

Answer 10

22' 3/4 - 18 = 4' 3/4...right?

Answer 11

i have -135/4

Answer 12

ack!!...someone get me a calculator lol

Answer 13

lol

Answer 14

2.25.... and thats my final offer :)


How you coming up with -135/4?

Answer 15

i mixed my #s lol but i have 9/4

Answer 16

20' 1/4
------
4 | 81
-8
-----
1
-0
---
1 <- remainder

Answer 17

9/4 is good :)

Answer 18

ok:D

Answer 19

20' 1/4
-18
--------
2' 1/4 = 9/4

Answer 20

sweet! :D