Question

Find the rectangular coordinates for the point whose polar coordinates are given.
(6√2, 5π/3)

Answer 1

\[x=rcos(\theta) , y=rsin(\theta)\]

Answer 2

\[ \sin(5\pi/3) = \sin(\pi/3) = (\frac{\sqrt{3}}{2})\]

Answer 3

For (6sqrt2))cos(5pi/3) I get 4.242640607. Do I round that up or what else?

Answer 4

what form do i put it in

Answer 5

\[\cos(5\pi/3) = - \cos(\pi/3) = -\frac{1}{2}\]

Answer 6

you can get exact values!,

Answer 7

they want exact values

Answer 8

do i not put the 6sqrt2 in the front

Answer 9

yeah, exact values

Answer 10

no, I was just finding the angles

Answer 11

the answers u gave are wrong.

Answer 12

is 1/2 the x value? and sqrt3/2 y

Answer 13

\[ x =-6\sqrt{2} \frac{1}{2} , y= 6\sqrt{2}\frac{\sqrt{3}}{2}\]

Answer 14

lol
plz dont tell u you put them in :(

Answer 15

^ thats the FINAL answer

Answer 16

i did.

Answer 17

well simplify it a bit

Answer 18

x = -3sqrt(2) , y= 3sqrt(6)

Answer 19

the answer for x seems very obscure

Answer 20

the other one's r wrong to

Answer 21

no their not

Answer 22

that's what the my hw program says. i hate it :P

Answer 23

x = 3sqrt(2) y = -3sqrt(6)

Answer 24

no,

Answer 25

5[pi/3 is in the 4th quadrant; +x, -y

Answer 26

wait lols , maybe

Answer 27

360-60 :)

Answer 28

yeh I was thinking 2pi/3 :|

Answer 29

amistre to the rescue: Thank you for all ur help eng :)

Answer 30

elec did al the hard stuff; got rid of the errors I would have done lol