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Mathematics 9 Online
OpenStudy (anonymous):

6÷2(1+2)=?

OpenStudy (anonymous):

Facebook!

myininaya (myininaya):

6dividedby2(3) 3(3) 9

OpenStudy (anonymous):

If only...

OpenStudy (anonymous):

1?

OpenStudy (anonymous):

Yes.

myininaya (myininaya):

no 9

myininaya (myininaya):

use order of operations

OpenStudy (anonymous):

Yeah, parenthesis first.

myininaya (myininaya):

the multiplication and division as it occurs left to right

myininaya (myininaya):

then not the

myininaya (myininaya):

division occurs first so 6 divided by 2=3 and then multiplication occurs 3(3)=9

OpenStudy (anonymous):

Yeah, yeah 9 we get it haha. No really, no lie. it is 9. 1 is common mistake, because of the whole pemdas.

myininaya (myininaya):

lol

myininaya (myininaya):

hey loco you figured out your polar question?

OpenStudy (anonymous):

6/2(1+2) =6/2(3) =3(3) =9

OpenStudy (anonymous):

not yet myininaya

OpenStudy (anonymous):

i need help really badly with it :(

OpenStudy (anonymous):

The one I was attempting to help on loco?

myininaya (myininaya):

did you try ising (x=rcos(pheta),y=rsin(pheta))

OpenStudy (anonymous):

yeah, but the answers i get are decimals and they don't work and i don't know how to get the exact value.

myininaya (myininaya):

deciamls? thats weird shouldn't be decimals do you have your calculator in radians?

OpenStudy (anonymous):

yeah, should i put it in degrees?

myininaya (myininaya):

no put in degrees if you are using degrees but 15pi is in radians

myininaya (myininaya):

so we are using radians

OpenStudy (anonymous):

Use a unit circle, not a calculator.

OpenStudy (anonymous):

I changed it to degrees, but the answer is still in decimals but the only thing is that it becomes negative.

myininaya (myininaya):

when i did I got (-1,0)

myininaya (myininaya):

right you could just use the unit circle

OpenStudy (anonymous):

how did u get that? can u show me

myininaya (myininaya):

thats what i did

OpenStudy (anonymous):

I would think it'd be much easier, avoid the calculator errors haha.

myininaya (myininaya):

cos(15pi)=cos(pi)=-1

myininaya (myininaya):

wait i forgot to multiply the 6 so it is (-6,0)

OpenStudy (anonymous):

(-1,0) are wrong says the hw program

OpenStudy (anonymous):

there we go that makes more sense

myininaya (myininaya):

lol

OpenStudy (anonymous):

no it's still wrong

myininaya (myininaya):

we are trying to evaluate (6cos(15pi)),6sin(15pi))

myininaya (myininaya):

what is it?

OpenStudy (anonymous):

(-6,0) is right.

OpenStudy (anonymous):

this is the original prob \[6\sqrt{3}, -6\]

OpenStudy (anonymous):

So the problem I tried helping you with?

myininaya (myininaya):

are we converting that to polar coordinates?

OpenStudy (anonymous):

Convert the rectangular coordinates to polar coordinates with r 0 and 0 θ 2π.\[r>0 and 0 \le \theta <\]

myininaya (myininaya):

ok i was doing converting (6,15pi) to polar my bad

myininaya (myininaya):

to cartesian*

OpenStudy (anonymous):

I had everything pretty much outlined for you on your post loco, well besides the answer.

myininaya (myininaya):

(12, 7pi/6)

OpenStudy (anonymous):

Wouldn't it be (12, 11pi/6)

myininaya (myininaya):

you might be right one sec..

myininaya (myininaya):

darn it you are right because cos(11pi/6)=sqrt(3)/2

OpenStudy (anonymous):

thanks you so much for taking ur time to help me guys. i wish i could give u real medals :)

OpenStudy (anonymous):

I wish I could receive a real medal haha you're welcome.

myininaya (myininaya):

what loco i wanted to draw you something k?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

YESSSSSSSSSSSSSSSSSSSSSSSSSSSS!!! Finally :O

myininaya (myininaya):

myininaya (myininaya):

when I drew the point (6sqrt(3),-6) it was just an approximation of where it would lie.

OpenStudy (anonymous):

Wow... u did that much work. I feel bad now :(

myininaya (myininaya):

why? the only reason i would do is because i enjoy lol. but do you why we use that cos^-1(sqrt(3)/2) instead of the others

myininaya (myininaya):

because its where our point lies

OpenStudy (anonymous):

oh ok

myininaya (myininaya):

so you completely get it?

OpenStudy (anonymous):

not completely, some of it. don't worry i'll be awake all night trying to understand it.

OpenStudy (anonymous):

can u try to help me on the other question i posted?

myininaya (myininaya):

ok go to it and i will follow you k?

OpenStudy (anonymous):

ok

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