Mathematics
9 Online
OpenStudy (anonymous):
6÷2(1+2)=?
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OpenStudy (anonymous):
Facebook!
myininaya (myininaya):
6dividedby2(3)
3(3)
9
OpenStudy (anonymous):
If only...
OpenStudy (anonymous):
1?
OpenStudy (anonymous):
Yes.
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myininaya (myininaya):
no 9
myininaya (myininaya):
use order of operations
OpenStudy (anonymous):
Yeah, parenthesis first.
myininaya (myininaya):
the multiplication and division as it occurs left to right
myininaya (myininaya):
then not the
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myininaya (myininaya):
division occurs first so 6 divided by 2=3
and then multiplication occurs 3(3)=9
OpenStudy (anonymous):
Yeah, yeah 9 we get it haha. No really, no lie. it is 9. 1 is common mistake, because of the whole pemdas.
myininaya (myininaya):
lol
myininaya (myininaya):
hey loco you figured out your polar question?
OpenStudy (anonymous):
6/2(1+2)
=6/2(3)
=3(3)
=9
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OpenStudy (anonymous):
not yet myininaya
OpenStudy (anonymous):
i need help really badly with it :(
OpenStudy (anonymous):
The one I was attempting to help on loco?
myininaya (myininaya):
did you try ising (x=rcos(pheta),y=rsin(pheta))
OpenStudy (anonymous):
yeah, but the answers i get are decimals and they don't work and i don't know how to get the exact value.
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myininaya (myininaya):
deciamls?
thats weird shouldn't be decimals
do you have your calculator in radians?
OpenStudy (anonymous):
yeah, should i put it in degrees?
myininaya (myininaya):
no put in degrees if you are using degrees but 15pi is in radians
myininaya (myininaya):
so we are using radians
OpenStudy (anonymous):
Use a unit circle, not a calculator.
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OpenStudy (anonymous):
I changed it to degrees, but the answer is still in decimals but the only thing is that it becomes negative.
myininaya (myininaya):
when i did I got (-1,0)
myininaya (myininaya):
right you could just use the unit circle
OpenStudy (anonymous):
how did u get that? can u show me
myininaya (myininaya):
thats what i did
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OpenStudy (anonymous):
I would think it'd be much easier, avoid the calculator errors haha.
myininaya (myininaya):
cos(15pi)=cos(pi)=-1
myininaya (myininaya):
wait i forgot to multiply the 6 so it is (-6,0)
OpenStudy (anonymous):
(-1,0) are wrong says the hw program
OpenStudy (anonymous):
there we go that makes more sense
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myininaya (myininaya):
lol
OpenStudy (anonymous):
no it's still wrong
myininaya (myininaya):
we are trying to evaluate (6cos(15pi)),6sin(15pi))
myininaya (myininaya):
what is it?
OpenStudy (anonymous):
(-6,0) is right.
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OpenStudy (anonymous):
this is the original prob
\[6\sqrt{3}, -6\]
OpenStudy (anonymous):
So the problem I tried helping you with?
myininaya (myininaya):
are we converting that to polar coordinates?
OpenStudy (anonymous):
Convert the rectangular coordinates to polar coordinates with r 0 and 0 θ 2π.\[r>0 and 0 \le \theta <\]
myininaya (myininaya):
ok i was doing converting (6,15pi) to polar my bad
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myininaya (myininaya):
to cartesian*
OpenStudy (anonymous):
I had everything pretty much outlined for you on your post loco, well besides the answer.
myininaya (myininaya):
(12, 7pi/6)
OpenStudy (anonymous):
Wouldn't it be (12, 11pi/6)
myininaya (myininaya):
you might be right one sec..
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myininaya (myininaya):
darn it you are right because cos(11pi/6)=sqrt(3)/2
OpenStudy (anonymous):
thanks you so much for taking ur time to help me guys. i wish i could give u real medals :)
OpenStudy (anonymous):
I wish I could receive a real medal haha you're welcome.
myininaya (myininaya):
what loco i wanted to draw you something k?
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
YESSSSSSSSSSSSSSSSSSSSSSSSSSSS!!! Finally :O
myininaya (myininaya):
myininaya (myininaya):
when I drew the point (6sqrt(3),-6) it was just an approximation of where it would lie.
OpenStudy (anonymous):
Wow... u did that much work. I feel bad now :(
myininaya (myininaya):
why? the only reason i would do is because i enjoy lol.
but do you why we use that cos^-1(sqrt(3)/2) instead of the others
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myininaya (myininaya):
because its where our point lies
OpenStudy (anonymous):
oh ok
myininaya (myininaya):
so you completely get it?
OpenStudy (anonymous):
not completely, some of it. don't worry i'll be awake all night trying to understand it.
OpenStudy (anonymous):
can u try to help me on the other question i posted?
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myininaya (myininaya):
ok go to it and i will follow you k?
OpenStudy (anonymous):
ok