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OpenStudy (anonymous):
Determine if (3+i -2) is an eigenvector of the matrix (-1 -2 / 5 -7) .. not division but under the first to numbers
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OpenStudy (anonymous):
use the definition
OpenStudy (anonymous):
if you multiply them do you end up with a scalar multiple of the matrix you started with? ( I am fairly sure thats the definition from memory )
OpenStudy (anonymous):
snce there are complex numbers I dont think its possible
OpenStudy (anonymous):
Av = Yv
OpenStudy (anonymous):
oh and that -2 is under the i
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OpenStudy (anonymous):
y is lamda?
OpenStudy (anonymous):
yeh
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
so the vector with two components is ( ( 3+i) , -2 ) ?
OpenStudy (anonymous):
Well it's written as a matrix
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OpenStudy (anonymous):
fairly sure answer is no
OpenStudy (anonymous):
Yes that is right. Did you just use the formula? How did you know it wasn't the vector?
OpenStudy (anonymous):
if you multiply them together you get ( -(7+i) , (1+5i) )
This is not a scalar multiple of the vector you started with
OpenStudy (anonymous):
Okay, so it can be a multiple?
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
\[Av=\lambda v\]
thats the definiton
OpenStudy (anonymous):
we multplied the two component vector with the matrix , and we didnt get a scalar multiple of the original vector , it doesnt satisfy the definition
OpenStudy (anonymous):
Oh okay, thank you!
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