Question

How to find the center and radius given the standard equasion?

Answer 1

standard equation for a circle?

Answer 2

For a circle
\[x^2+y^2+2gx+2fy+c=0\] ,
center is (-g,-f) and radius is \[\sqrt{g^2+f^2-c}\]

Answer 3

Weird I've never seen that form for a circle.
In most cases I see it as
\[ax^2 + b^2= c^2\]
where a=b
where the radius is\[\sqrt{c^2}\]

Answer 4

\[ax^2+ by^2=c^2\] woops wrote it wrong.

Answer 5

Erm..

Standard equation for a circle is
\[(x-h)^2 + (y-k)^2 = r^2\]

If you put multiplicative constants out front that aren't equal you'll end up with an ellipse.