need to solve inequality in interval notation and algebraic notation.
\[x+2 \over x+6 \]>0
the x+2 is a fraction over x+6 and it's supposed to be in a straight line with >0
okay flip it. so we get (x+6)/(x+2)>0 x+6 = x+2 +4 1+4/(x+2)>0 4/(x+2) > -1 4>(-x-2) 4<(x+2)
sorry the last step is -4 < x+2
got it?
oh ok. yeah, makes sense. so which one is the interval notation and which ones the algebraic. Just to clarify?
it says to separate answers in algebraic notation with or if necessary. I wasn't sure if there was more than one.
oh I didnt see that part of the problem. x > -6 is the algebraic notation x = {-5 to +infinity} (or something like that) would be interval notation. the two are different methods of expressing all the values x can take. you can either say x is greater than negative 6 ( x>-6) or you can say x can take any value between -5 and positive infinity x = {-5 to +infinity} I don't remember how the interval notation works. google it.
ok so the only think I should put down for algebraic notation is \[x >-6\]? I don't think it wants me to say the same thing twice, It might want me to put or in between if their is another solution?
there is no 'other' solution. x lies in a certain interval. How you say that x lies in a certain interval changes. You can either say x> 6 but x<9 or you can say x lies between 6 and 9.
The problem states you need to express it in both notations.
ohh I see what you were saying. ok. Thanks
lol, you are welcome.
think \[-5,\infty\] is the answer to the other part of the problem? or should I double check somewhere?
for the interval notation.
would this be either of the answers? http://www.wolframalpha.com/input/?i=%28x%2B2%29%2F%28x%2B6%29%3E0
Yes, that is right. the first solution is the algebraic notation. the second solution is the interval notation, only it is expressed in graphical form.
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