Question

The second derivative of (4-x^2)*exp(-1.16x^2)

Answer 1

can anyone help me with this?? =]

Answer 2

you can use the product rule right?

Answer 3

h(x)=f(x)g(x)

h(x)=f(x)g(x)=f(x)g(x)+f(x)g(x)

Answer 4

h'(x) = [f(x)g(x)]' = f'(x)g(x)+f(x)g'(x)

Answer 5

yes but it doesn't work. my online program does not accept it. (4-x^2)(5.3824*^2*exp(-1.16x^2)-(-2.32xexp(-1.16x^2)(-2x)-(exp(-1.16x^2)(-2)-(-2x)(-2.32xexp(-1.16x^2)

Answer 6

is that what you got?

Answer 7

I didn't work it out. I was just pointing out that you can use the product rule for this kind of problem.

Answer 8

i did. do you think you can check my work?

Answer 9

but your solution seems correct. see if you can simplify it further. Maybe your online tool will accept it then

Answer 10

I think I am getting a slightly different answer from you. check your calculations.

Answer 11

what is slightly different about it? I just double checked!

Answer 12

did you simplify it. wait let me post my solution

Answer 13

you can set x^2 = y and factor the second term.

Answer 14

as a quadratic equation of course.