find the zeros and the minimum or maximum for the relation y=x^(2)+2x-24

Question

anonymous · Answer

1) To find the zeros, set your function equal to zero:
$$x^2+2x-24=0 \implies (x+6)(x-4)=0 \implies x=-6,x=4$$
So,  y has to zeros x=-6 and x=4.

anonymous · Answer

Is this a calculus course?!

anonymous · Answer

If so, then to find the extrema (either maximum or minimum), Do the following:
1) Find the derivative.
2) Set the derivative equal to zero, and solve for x. That value is a critical point (where extreme values occur).
3)Substitute this value in the original function, this will be your extreme value.

anonymous · Answer

To see if it's a maximum or a minimum, just compare it with any other value of y. If it's greater, then it's a maximum. If it's smaller, then it's a minimum.

anonymous · Answer

Are you following?

anonymous · Answer

I think he left for a break? ._. lol