Question

The number of websites is growing by 15% percent each month. In June 2005, there were 4000 websites.

Write a formula for the number of websites as a fuction of months since june 2005.

And hOW LONG WILL IT TAKE FOR THE NUMBER OF SITES TO reach 8000 and 16000?

Answer 1

15*12*...maybe something like this

Answer 2

lol thinker, still here? :)

Answer 3

going going lol

Answer 4

scoot =P

Answer 5

Let y be the number of websites, and x the number of months. A relationship that represents them is given by:
y=4000+0.15x.

Answer 6

\[y=4000+0.15x \rightarrow (*)\]

Answer 7

To find how long it will take to reach a certain number of websites, just plug that number in y, and then solve for x.

Answer 8

you mean solve for y, right anwar?

Answer 9

No. I mean solve for x, since x represents the months and y represents the number of websites.

Answer 10

but she wants the number of websites and not months

Answer 11

wait, nvm lol, I misread the question >_<

Answer 12

my bad ^_^

Answer 13

Let's take the first one, reaching 8000.

Answer 14

wait can you tell me the formula aginain with T being the input variable

Answer 15

Just put T instead of x.

Answer 16

ok

Answer 17

so now will you help me with pluging the nubers in

Answer 18

So, let's do the part when it reaches 8000 websites. Substitute in (1) by "y=8000":
\[y=4000+0.15x \implies 8000=4000+0.15x \rightarrow(1)\]
Solving equation (1), by first subtracting 4000 from both sides and then dividing by 0.15

Answer 19

OMG.. I got a large number that does not seem right to me.

Answer 20

Just let me check my steps.

Answer 21

Oh I did a big mistake. My first step wasn't right. The problem is much more complicated.

Answer 22

Ok. Focus now. let y be the number of websites, and T the number of months, the relation is given by:
\[y={0.15y \over x}+4000 \rightarrow(1)\]

Answer 23

I meant:
\[y={0.15y \over T}+4000\]

Answer 24

tha is the formula

Answer 25

Yeah!! the first one was wrong.

Answer 26

Sorry about that.

Answer 27

you can simplify it more, or just leave it as it is.

Answer 28

Now plug y=8000, and solve for x:
\[8000={0.15(8000) \over x}+4000 \implies 8000x=1200+4000x \implies 4000x=1200\]
\[\implies x={1200 \over 4000} \implies x=0.3\]
That means it would take 0.3 months (9 days) to reach to 8000 websites.

Answer 29

Similarly, You can do it for 16000.

Answer 30

OK I GOT IT

Answer 31

Good!! I hope it makes sense to you :)

Answer 32

if it is increasing by 15%per month then how can it double in just 9 days

Answer 33

^^ point :(

Answer 34

OK CAN YOU HELP ME WITH ANOTHER pROMBLEM . ACTUALLY it was solved earlier by someone else but They got it wrong I want to see if you will guide me the right way

Answer 35

ok i will try but it may take few minutes

Answer 36

TW= I(1 + r/q)nq
TW-total web
I-initial web
q-number of months
n-number of years

Answer 37

r-rate

Answer 38

At a concert By the Who in 1976, the sound level 50 meters from the stag registered 120 decibles. The treshold of pain for the human ear is 90 decibles. Calculate the sound intensity of the Who concert and the sound intenisity of the treshold of pain.

Answer 39

can u help me with this qetion please jas

Answer 40

i m sorry
i m not sure about it