Question

Linda invests $13,000 for one year. Part is invested at 4%, another part at 5%, and the rest at 7%. The total income from all 3 investments is $705. The combined income from the 4% and 5% investments is $75 more than the income from the 7% investment. Find the amount invested at each rate.

Answer 1

x*0.04+y*0.05+(13000-x-y)*0.07=705
x*0.04+y*0.05-(13000-x-y)*0.07=75
solve for x and y

Answer 2

theres no z to it?

Answer 3

im so lost...

Answer 4

no there is no need

Answer 5

as z=13000-x-y

Answer 6

i still dont understand how to solve it...

Answer 7

let money invested for 4% be x
let money invested for 5% be y
so money invested for 7% is money left i.e 13000-x-y

Answer 8

ok.....

Answer 9

now total income is the sum of income from all
so it's 1 eq
now use second condition

Answer 10

ugh... im never gonna get this...

Answer 11

try it i will help u to get it
never lose hope
always try and u will get it

Answer 12

ok let me try, give me a few

Answer 13

im not gettin it because whatever I have it is cancellin x and y

Answer 14

so I cant solve for neither

Answer 15

have u solved 2 eq which i gave u?

Answer 16

ok i made a mistake,
I got x=-13000, and y=9250

Answer 17

an z=16750
which are all probably wrong

Answer 18

k iet me check again

Answer 19

ok

Answer 20

(1)-(2) will give u value of z
i.e 5571.4285..

Answer 21

now solve others

Answer 22

ok now u lost me...

Answer 23

can somebody please help me solve this problem...

Answer 24

Interest Rate * Amount Loaned = return or return on interest or revenue
Borrowing from Jas's work we have the following:

Let x = amount loaned at 4% or 4/100 Note: 4/100 is 4% converted to a fraction.
Let y = amount loaned at 5% or 5/100
The remaining cash is loaned at 7% or 7/100

The total income from all 3 investments is $705.\[\left(\frac{4}{100}x\right)+\left(\frac{4}{100}y\right)+\left(\frac{7}{100}(13000-(x+y))\right)=705 \]
Solve the above equation for y now; we will need it later. Multiply through by 100, gather all of the y terms and put them on the left hand side and all of the other terms on the right hand side and then simplify.
\[y= \frac{1}{2} (20500-3 x) \]
The combined income from the 4% and 5% investments is $75 more than the income from the 7% investment. Since the left hand side is 75 more than the right, we add in an additional 75 to the right hand side to make both sides equal to each other.
\[\left(\frac{4}{100}x\right)+\left(\frac{5}{100}y\right)\text{= }75+\frac{7}{100} (13000-(x+y))\]
Solve for y.
\[y= \frac{1}{12} (98500-11 x) \]
Set the right hand sides of the y= equations above to each other as follows:
\[\frac{1}{2} (20500-3 x)\text{=}\frac{1}{12} (98500-11 x)\]
and solve for x.
\[x=3500, y=\frac{1}{12} (98500-11*3500)=4500, 13000-3500-4500 =5000\text{ } \]

Answer 25

There is an error in the first equation expression.
\[\left(\frac{4}{100}y\right)\text{ should be changed t}\text{o }\left(\frac{5}{100}y\right)\]
The computations were used with the latter.

Answer 26

this is the same as i answered earlier

Answer 27

Jas,
The reason I put forth a solution was because after all of yesterday's back and forth on this problem, hermommy1101 in the last problem posting yesterday, issued a plea,

"can somebody please help me solve this problem..."

Just trying to help out.