Question

solve by completing the square.

Answer 1

x\[x ^{2}+2x=24\]

Answer 2

move all one side you get\[x^{2} +2x -24 =0\]

Answer 3

now you factour(x+6)(x-4)

Answer 4

x=-6
x=4

Answer 5

\[2x ^{2}-4x-3=0\]

Answer 6

this is quadratic equation form:
[-b±√(b^2-4(a)(c))]/(2(a))
a=2
b=-4
c=-3
[-(-4)±√((-4)^2-(4*2*(-3))]/(2*2))
[(4)±√(16+24)]/(4)
[(4)±2√(10)]/(4)
x =1/2[±√(10)]

Answer 7

The above method is not "completing the square"

Answer 8

annette the second you want do complete square?

Answer 9

Even in first one, it is splitting the middle term method and not completing the square

Answer 10

Thank you Harkirat for remind me
let do again , can you do second one it late I have to go
2/2=1 , 1^2 =1
(x+1)^2=24+1
(x+1)^2=25
x +1 = √(25)
x = -1± 5
x=-6 or x= 4

Answer 11

For the second we proceed as follows:
\[2x ^{2}-4x-3=0\]

Answer 12

First we take -3 to RHS as 3\[2x ^{2}-4x=3\]

Answer 13

Next we divide both sides by 2 (to get rid of the 2 in front of x^2)
So we get
\[x ^{2}-2x=3/2\]

Answer 14

Now to complete the square we add 1^2 to both sides
\[x ^{2}-2x+1^{2}=3/2 + 1\]

Answer 15

Now left side is a complete square as follows
\[(x-1)^{2}= 5/2\]
This gives
\[x-1 = \pm \sqrt{5/2}\]
Now taking -1 to RHS we get the final answer
\[x = 1 \pm \sqrt{5/2}\]

Answer 16

So the two roots/zeros of the given quadratic equation are
\[1+\sqrt{5/2}\] and \[1-\sqrt{5/2}\]