Question

use the exact method to solve the DE:

2xydx + x^2ydy=0

Answer 1

Are you confused as to how it's done? Just wanting to check your answer or what?

Answer 2

i checked for exactness and it wasn't exact so I used the next method to check for exactness and it looks as thought I got something but unsure

Answer 3

It doesn't look exact to me because the term on the left has an extra y in it.

Answer 4

using the test for exactness it doesnt come out exact but when you use integrating factors to solve then it works

Answer 5

its not an exact diff equation.
divide throughout by x^2y and reduce it to separable form and solve it. its easy

Answer 6

if i used integrating factor method i was tuahgt to do if it doesnt come out exact then i get the integrating factor of e^(y-ln(y))

Answer 7

how did u check the exactness?

Answer 8

partial derivative of M with respect to y and partial derivative of N with respect to x and see if they are equal

Answer 9

P(x,y)=2xy
Q(x,y)=x^2y for exactness
partial derivative of p w.r.ty=partial derivative of Q w.r.t x

Answer 10

there is a method uzma ,differentiate the term with dx with respect to y and the term with dy with respect to x ,if both differentiated terms become equal then they r exact,otherwise non exact

Answer 11

yes right :)

Answer 12

com for chat uzma

Answer 13

so what do u guess about the exactness?

Answer 14

when doing that they come out non exact and then there is a method to use after that where you use integrating factors after applying an equation and then go from there

Answer 15

not exact initially

Answer 16

any help??

Answer 17

the eq is exact

Answer 18

non exact...m sorry :)

Answer 19

so the eq can made by multiplying with intgrating factor