Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
no!
OpenStudy (anonymous):
:p
OpenStudy (anonymous):
y
OpenStudy (anonymous):
i have urgent problem
OpenStudy (anonymous):
u can ask,but no guarantee for the solution :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
my question is:
If the momentum of a moving object is increased by 100%. Than the Kinetic energy of that object will be increased by :
OpenStudy (anonymous):
p = mv = momentum
OpenStudy (anonymous):
K = kinetic energy = (1/2)mv^2
OpenStudy (anonymous):
if we double momentum, that means instead of p = mv , we have p=2mv
OpenStudy (anonymous):
now , p = 2K/ v
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so K = pv/2
OpenStudy (anonymous):
wait, think I went round in a circle :|
OpenStudy (anonymous):
but its just playing with equations, and ratios
OpenStudy (anonymous):
KE = 1/2* mv^2
= 1/2* p* v
OpenStudy (anonymous):
I think we can safely assume that all the in increase in momentum is due to velocity, not a change in mass
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
that makes it much easier
OpenStudy (anonymous):
i guess kinetic energy would be doubled
OpenStudy (anonymous):
so we essentially double our velocity
OpenStudy (anonymous):
which quadruples our kinetic energy
OpenStudy (anonymous):
we square velocity in the equation
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ie times by 4
OpenStudy (anonymous):
bad explaination
Kinetic energy of object mass m, velocity v: = (1/2) m v^2
Kinetic energy of object mass m , velocity 2v : = (1/2) m (2v)^2 = (1/2) m v^2 (4) = 4K