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Mathematics 14 Online
OpenStudy (anonymous):

can i ask a physics question pls .......

OpenStudy (anonymous):

no!

OpenStudy (anonymous):

:p

OpenStudy (anonymous):

y

OpenStudy (anonymous):

i have urgent problem

OpenStudy (anonymous):

u can ask,but no guarantee for the solution :)

OpenStudy (anonymous):

my question is: If the momentum of a moving object is increased by 100%. Than the Kinetic energy of that object will be increased by :

OpenStudy (anonymous):

p = mv = momentum

OpenStudy (anonymous):

K = kinetic energy = (1/2)mv^2

OpenStudy (anonymous):

if we double momentum, that means instead of p = mv , we have p=2mv

OpenStudy (anonymous):

now , p = 2K/ v

OpenStudy (anonymous):

so K = pv/2

OpenStudy (anonymous):

wait, think I went round in a circle :|

OpenStudy (anonymous):

but its just playing with equations, and ratios

OpenStudy (anonymous):

KE = 1/2* mv^2 = 1/2* p* v

OpenStudy (anonymous):

I think we can safely assume that all the in increase in momentum is due to velocity, not a change in mass

OpenStudy (anonymous):

that makes it much easier

OpenStudy (anonymous):

i guess kinetic energy would be doubled

OpenStudy (anonymous):

so we essentially double our velocity

OpenStudy (anonymous):

which quadruples our kinetic energy

OpenStudy (anonymous):

we square velocity in the equation

OpenStudy (anonymous):

ie times by 4

OpenStudy (anonymous):

bad explaination Kinetic energy of object mass m, velocity v: = (1/2) m v^2 Kinetic energy of object mass m , velocity 2v : = (1/2) m (2v)^2 = (1/2) m v^2 (4) = 4K

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