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two astronauts are pulling on each other with a rope. one pulls 30 N to the right, the other pulls 20 N to the left. What is the tension in the rope when the force is applied? We can assume the guy pulling 30 N is 50kg and the guy pulling 20 N is 40 kg, but thats not relevant.
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any ideas?
Let me pull out my old physics notes.
Newton's 2nd law, particle under a net force
The rope is being pulled in one direction (force of 30 N times 50 kg mass) subtract the other direction (force of 20 N x 40 kg) = result is the tension in the rope.
I want to reconsider. Force of 30 one direction, force of 20 the other. Net force of 10. Tension is `10N
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