Question

lim as t-> ∞ [arctan(t)]

Answer 1

LOLWUT.

Answer 2

pi/2

Answer 3

If you look at the graph of tan(t) there are asymptotes every pi/2 radians. So, if you inverse the image of tan(x) on a graph, you can see that there is an asymptote at y=pi/2 and y=-pi/2. So, if you extend to infinity the limit approached pi/2 and if you extend to -infinity, the limit approaches -pi/2.

Answer 4

ok thanks