Ten students are applying for 3 positions on a team. the students include 4 boys (adam, alex, anthony, and arnold) and 6 girls (abbey, aurora, agnes, alice, amanda, and anna). all the students have an equal chance of being selected. find the probability that the students selected will include: a) 3 girls b) 1 boy and 2 girls c) at most 1 girl d) adam, anthony, and alice e) agnes and 2 other students

Question

amistre64 · Answer

6 in 10 that it has 1 girl.. ithink :)

anonymous · Answer

This is a fundamental counting princple problem:

(a) we need all three to be girls. The number of ways we can select three girls is 6 * 5 * 4 (since there is no replacement). The number of all selections is 10 * 9 * 8. Thus, P(3 girls) = (6*5*4)/(10*9*8)

amistre64 · Answer

no replacement accounts for the duplicates right?

anonymous · Answer

yea

anonymous · Answer

(b) 1 boy and 2 girls is similar to above. Since order is not important, we have 4 * 6 * 5,
4 boys, then 6 girls and then 5 girls. The probability of all is still 10*9*8.

(a) duplicates? yea, it means after we pick a girl we don't pick her again.

anonymous · Answer

can u do it using permutations and combinations please

anonymous · Answer

No. I know they teach it that way, but I think that is a bad way to go. Understanding it this way helps you solve every question, not just the ones in the form you're familiar with.