Question

find the equation of the line that passes through P (2,2,-3) and is paralel to the line 3(x-2)=2(y-2)=6(z+3)?

Answer 1

are those equa;l signs spoose to be (+) signs?

Answer 2

the normal vector appeart to be <3,2,6> assuming those are sposed to be (+) signs

Answer 3

the equation appears to be:

3x-6 +2y-4 +6z+18 = 0

3x + 2y +6z +8 = 0 would be the eqaution of the plane

Answer 4

no i wrote it as it is

Answer 5

that isn't in the answer choices

Answer 6

what are the answer choices :)

Answer 7

ok give me a secon it's kind of a lot to type out

Answer 8

k

Answer 9

its looks line parametric representation of the line... what is the topic of your study?

Answer 10

a) x=2+2t, y=2+3t, z=-3+t b)x=2+3t, y=2+2t, z=-3+6t c)x=2+2t, y=2-3t, z=-3-t d)x=2+3t, y=2-2t, z=-3-6t

Answer 11

this is cal 3...can you help?

Answer 12

still there?

Answer 13

a) x=2+2t, y=2+3t, z=-3+t

b)x=2+3t, y=2+2t, z=-3+6t

c)x=2+2t, y=2-3t, z=-3-t

d)x=2+3t, y=2-2t, z=-3-6t


my guess is (b) but i have no proof to back that up......its been awhile :)

Answer 14

ok thanks for looking

Answer 15

To find the parametric equations of the line passing through the point (2,2,-3) and parallel to the vector <3,2,6>.

We first find the vector equation of the line. Here, r_0=<2,2,-3> and v=<3,2,6>.

Thus, the line has vector equation r=<2,2,-3>+t<3,2,6>.

The parametric equations of the line are:

x=2+3t, y=2+2t, and z=-3+6t. [B]

Answer 16

copied that off the web and included your numbers :)

http://www.math.oregonstate.edu/home/programs/undergrad/CalculusQuestStudyGuides/vcalc/lineplane/lineplane.html