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Mathematics 7 Online
OpenStudy (anonymous):

Ten students are applying for 3 positions on a team. the students include 4 boys (adam, alex, anthony, and arnold) and 6 girls (abbey, aurora, agnes, alice, amanda, and anna). all the students have an equal chance of being selected. find the probability that the students selected will include: a) at most 1 girl b) adam, anthony, and alice c) agnes and 2 other students

OpenStudy (anonymous):

no idea

OpenStudy (anonymous):

hey INewton

OpenStudy (amistre64):

we could always do this the long way :) and make a tree or chart

OpenStudy (amistre64):

i havent been good yet at finding and filtering out all the redundnat possibilities :)

OpenStudy (anonymous):

can u do it using permutations and combinations?

OpenStudy (amistre64):

not yet, taking stats this summer...can you wait til august :)

OpenStudy (anonymous):

ur taking ap stats?

OpenStudy (amistre64):

college class...

OpenStudy (amistre64):

im too old for ap i think

OpenStudy (anonymous):

oh do u know the answers though???

OpenStudy (amistre64):

not any anwers that i would trust; is there a multiple choice with this?

OpenStudy (anonymous):

no

OpenStudy (amistre64):

I know that with 3 positions avaiable; there are 10*9*8 possibilities; but how to remove the duplicates eludes me at the moment

OpenStudy (amistre64):

we can always try to work with a similar situation; such as 2 spots to fill and 4 people; then see how to eliminate the duplicates

OpenStudy (anonymous):

try it

OpenStudy (anonymous):

The idea is that you try it.

OpenStudy (anonymous):

(although admittedly it's not personally how I would do it - but I hate statistics anyway)

OpenStudy (amistre64):

dividing the total by 2 worked in that case on paper; let me try another

OpenStudy (anonymous):

?????

OpenStudy (amistre64):

11 21 31 41 12 22 32 42 13 23 33 43 14 24 34 44

OpenStudy (amistre64):

cross off all the duplicates

OpenStudy (amistre64):

12 13 23 14 24 34

OpenStudy (amistre64):

the total possible combination of 4 people and 2 spots is: 4*3/2

OpenStudy (amistre64):

its the same for 5 people and 2 spots: 5*4/2

OpenStudy (amistre64):

i wonder whatll happen with 3 spots...

OpenStudy (anonymous):

??????

OpenStudy (amistre64):

4 people and 3 spots has 4 possibilities

OpenStudy (amistre64):

how we factorial that I dont know...

OpenStudy (amistre64):

3C4 maybe.. let me find an online cal

OpenStudy (amistre64):

the formula is: people! ----------------- spots!(people-spots)!

OpenStudy (amistre64):

and thats the best i can do for you at the moment...

OpenStudy (amistre64):

there seems to be 120 possible combonations; without repetition in all

OpenStudy (anonymous):

wait, so what's c d and e??

OpenStudy (amistre64):

4 boys can form an all boy team 4 times; so I would think that the rest are sure to have at least 1 girl; 116 out of 120 is sure to have at least 1 girl

OpenStudy (amistre64):

c is agnus plus 2 other students; so we can take agnus out of the mix and have 2 spots to fill; 9! ------- = 36 2!(9-2)!

OpenStudy (amistre64):

36 out of 120

OpenStudy (amistre64):

what does it mean by positions? like captain, assistant, and runner? then we can have duplicates, just not the same person in all 3 spots and that changes things

OpenStudy (anonymous):

d is 36/120???

OpenStudy (anonymous):

????????

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