(3^-1xy^-4z^5)/(7x^-4y^2z)
- Simplify Completely

Question

(3^-1xy^-4z^5)/(7x^-4y^2z) 
- Simplify Completely

anonymous · Answer

(I got 9y^12z^2)/(-14x^10z^10)

anonymous · Answer

First write all the variables in the places they should be. If it's negative, it switches from top to bottom, or vice versa.

Then we get:
$$x z ^{5} x ^{4} \div 3 (7) y ^{4} y ^{2} z$$

Then you combine like terms:
$$x ^{5} z ^{5} \div 21 z y ^{6}$$

Then finally you cancel the exponents that you can. The only one you can change is the z, so it becomes:
$$x ^{5} z ^{4} \div 21 y ^{6}$$

anonymous · Answer

ohhh... I missed something in my problem... I forgot about the ( )^-2 that surrounds the problem

anonymous · Answer

Oh, thats okay. You still do the same thing. Only take all of my answer, flip all of them, ie the bottom becomes the top and vice versa, and square them all. It doesn't change anything other than that.

anonymous · Answer

But to save another explanation, if a fraction is surrounded by (  )^-2, don't you take the top part of the problem and move it to the bottom?

anonymous · Answer

Yes, then multiply all the exponents by 2, and the 21 is squared.

anonymous · Answer

Okay great, tyvm for taking the time to help me :D

anonymous · Answer

Sure no problem! I like medals if it helped haha

anonymous · Answer

Oh it did