Question

evaluate the integral

Answer 1

\[\int\limits_{?}^{?}(x ^{2}-x+1) dx/ x ^{2}-x\]

Answer 2

You have to give us a hint. Which part of the book are you at?

Answer 3

hehe. partial functions

Answer 4

\[LHS =A/(X-1) +B(x+1)\]

Answer 5

B/(x+1)

Answer 6

umm.... wouldn't it be Ax+B/x^2+x? or are you skipping steps

Answer 7

Oh, I haven't done these in a while, may be you should start it.

Answer 8

Oh, the bottom is not the difference of two squares, I misread it.

Answer 9

can you only use long division if the denominator is the difference of two squares?

Answer 10

\[LHS =A/x + B/(x-1)\]

Answer 11

are you sure?

Answer 12

\[x ^{2}-x=x(x-1)\]

Answer 13

okay so what should I do next

Answer 14

You can handle it now. It is cut up in small bites that you can chew on.

Answer 15

I got A = -1 and B =1 but when I find the integral my denominator = 0 :/

Answer 16

what , just equals -ln(x) +ln(x-1) +C

Answer 17

can be simplifed as ln [ (x-1)/(x) ] +C